7(4^(2x))=28(4^x)

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Solution for 7(4^(2x))=28(4^x) equation: 



7(4^(2x))=28(4^x)

We move all terms to the left:

7(4^(2x))-(28(4^x))=0

determiningTheFunctionDomain
74^2x-284^x=0

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